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Vanadium(V) chloride

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(Redirected from Vanadium pentachloride)
Vanadium(V) chloride
Names
Other names
vanadium pentachloride
Identifiers
3D model (JSmol)
  • InChI=1S/5ClH.V/h5*1H;/q;;;;;+5/p-5
    Key: RPESBQCJGHJMTK-UHFFFAOYSA-I
  • Cl[V](Cl)(Cl)(Cl)Cl
  • dimer: Cl[V-]1(Cl)(Cl)(Cl)[Cl+][V-]([Cl+]1)(Cl)(Cl)(Cl)Cl
Properties
Cl10V2
Molar mass 456.38 g·mol−1
Appearance black solid
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Vanadium(V) chloride is the inorganic compound with the formula VCl5. It is a black diamagnetic solid. The molecules adopt a bioctahedral structure similar to that of niobium(V) chloride.[1]

Preparation and reactions

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Chlorine cannot oxidise vanadium(IV); chlorination of vanadium metal will yield only vanadium(IV) chloride. Vanadium(V) chloride is instead prepared from vanadium pentafluoride with excess boron trichloride as a chlorinating agent:

2 VF5 + 10 BCl3 → [VCl5]2 + 10 BF2Cl

It is unstable at room temperature with respect to vanadium(IV) chloride, which releases gaseous chlorine:

[VCl5]2 → 2 VCl4 + Cl2

In contrast, the heavier analogues NbCl5 and TaCl5 are stable and not particularly oxidizing.

References

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  1. ^ Tamadon, Farhad; Seppelt, K. (2012). "The Elusive Halides VCl5, MoCl6, and ReCl6". Angewandte Chemie International Edition. 52 (2): 767–769. doi:10.1002/anie.201207552. PMID 23172658.