Talk:Electromagnetic shielding

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I would like to see some of the physics behind this concept

{{Expand}} I would like to see some of the physics behind this concept, instead of a general "this is the definition of shielding." - eykanal

It would also be a very good idea to quickly explain what "coupling" means. - Raeyin

RF shielding doesn't really cover anything that's specific to the field of RF. It should be merged here for now. — Omegatron 15:44, 23 March 2006 (UTC)[reply]

eykanal: see the page on a farady cage for more info.

Jenke: RF shielding can be quitte different to EM shilding, if the entries are similar then this needs to be addressed.

In the intro I changed the bit about "static magnetic fields" to "static or low-frequency magnetic fields". Also, on the "be bold with edits" principle, I removed "visible light" from the things shielded against. It is certainly true that a solid metal shield will block visible light, but there are a lot of very effective EM shields that don't block much visible light; and a lot of things that block visible light are not EM shields at all. (Er, well, they are, but only at very very short wavelengths!) I think the "visible light" claim is an example of something that is technically correct but practically misleading. Reply here, or revert, as you see fit! :) Jeh 06:08, 19 January 2007 (UTC)[reply]

WikiProject class rating

This article was automatically assessed because at least one WikiProject had rated the article as start, and the rating on other projects was brought up to start class. BetacommandBot 09:49, 10 November 2007 (UTC)[reply]

Was looking for info on magnetic shielding and for some reason was redirected here. Decided to add a section on shielding and also created a references section. Not really happy with the section so I hope someone with more expertise will edit it. --Parabolis (talk) 01:33, 10 December 2007 (UTC)[reply]

what does "ground" have to do with the process?

"conductive layer of metal, which can be electrically connected to the chassis ground of the equipment, thus providing effective shielding." I'm under the impression grounding a conductive material has something to do with the process of shielding radiation but am not entirely sure. I might understand the characteristics of a shield as follows, someone edit something like this in with elaboration if you know how it works. "for a electromagnetic shield you must have (1) a conductive material between a source of radiation and bla, (2) the conductive material must be grounded, (3) gaps in the material must be much smaller than the wave legth of the radiation being attenuated."

Student Use

I myself am a student, and I and others find Wikepedia a very useful research site. I generally however find it useful to have dictionary.com running aswell! This is because of the complex scientific language used throughout the site. I myself am in my top Science set at school and am gifted and talented, however I think this particular article definitely needs a bit of translation. Some people are probably put off by the very first sentance! For I think it doesn't really explain simply to begin. The detail is supposed to be added later on in the aticle. Please do not hate me for this comment, as said I and my fellow students really enjoy this site! —Preceding unsigned comment added by 81.178.73.198 (talk) 17:28, 17 January 2009 (UTC)[reply]

Magnetic Attraction

Are there any materials that shield magnetism but are not themselves attracted to magnets?Ratsbew (talk) 16:59, 12 April 2009 (UTC)[reply]

In the old tube type radios they had aluminum shields around the tubes for RF shielding; and they would probably develop internal currents such as to provide some amount of variable magnetic field shielding.WFPM (talk) 06:06, 17 February 2012 (UTC)[reply]

In generating stations, isolated-phase bus cancels the magnetic field produced by heavy currents by enclosing the generator leads in an aluminum tube; currents induced in the tube creat a field that nearly cancels the field produced by the current in the generator lead. But in the static case, unless you can inject a current from some other source to cancel the field, anything you use for shielding is going to have to have a higher permeability than air, and so, will stick to a magnet. --Wtshymanski (talk) 14:37, 17 February 2012 (UTC)[reply]

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No mention of TEMPEST?

https://en.wikipedia.org/wiki/Tempest_(codename) TEMPEST is a National Security Agency specification and a NATO certification [1][2] referring to spying on information systems through leaking emanations, including unintentional radio or electrical signals, sounds, and vibrations.[3] TEMPEST covers both methods to spy upon others >>> and how to shield equipment against such spying <<<. The protection efforts are also known as emission security (EMSEC), which is a subset of communications security (COMSEC).[4] — Preceding unsigned comment added by 173.81.169.7 (talk) 20:31, 15 April 2018 (UTC)[reply]

Vector(r) - Vector(theta) does not equal Vector (z)

In the mathematical model section the mathematical model is postulated as Ho*Vector(z)=H_r*Vector(r) - H_rho*Vector(theta)

If that would be the case then How would it work if theta was 90 degrees or pi/2 ? the component that has to be used is rho axis vector (as in rho=r*sin(theta)) (cylindrical coordinates) (rho=sqrt(x^2+y^2)).

z is not part of the spherical coordinates system but of cartesian and cylindrical. you cannot do Vector(r)-Vector(theta) and expect to have Vector(z). Ctmv (talk) 14:43, 2 September 2023 (UTC)[reply]